Math, asked by lonetawseef548, 7 months ago

ark : Notice, 6 x 12 x 120 HICF (6, 12, 120) * LCM (6, 12,
doet of three numbers is not equal to the product of their HCF and
(i) 140
EXERCISE 1.2
Express cach number as a product of its prime factors
(ii) 156
(v) 5005
Find the LCM and HICF of the following pairs of integers and verify the
product of the two numbers,
© 26 and 91
(1) 510 and 92
(iii) 336 an
Find the LCM and HCF of the following integers by applying the pr
method
0 x2, 15 and 21 (11) 17.23 and 29
(iii) 8,9 a​

Answers

Answered by mohnishkrishna05
0

:

Mark Me As Brainliest And Thank Me If The Answer Is Useful.

-- :

Using prime factorisation method:

(i) 12, 15 and 21

Factor of 12=2×2×3

Factor of 15=3×5

Factor of 21=3×7

HCF (12,15,21)=3

LCM (12,15,21)=2×2×3×5×7=420

(ii) 17, 23 and 29

Factor of 17=1×17

Factor of 23=1×23

Factor of 29=1×29

HCF (17,23,29)=1

LCM (17,23,29)=1×17×23×29=11,339

(iii) 8, 9 and 25

Factor of 8=2×2×2×1

Factor of 9=3×3×1

Factor of 25=5×5×1

HCF (8,9,25)=1

LCM (8,9,25)=2×2×2×3×3×5×5=1,800

Similar questions