Question

Armaan has a rectangular garden of length and breadth 168 upon 5 metre and 135 upon 16 respectively find the cost of fencing of the garden five ground at the rate of 21 upon 2 rupees per metre

Answer 1

GivEn:-

• Length of Rectangle = $\sf \dfrac{168}{5}\;metre$

• Breadth of Rectangle = $\sf \dfrac{135}{16}\;metre$

To find:-

• Find the cost of fencing of the garden five ground at the rate of 21 upon 2 rupees per metre?

SoluTion:-

⋆ Rectangle!♡

$\setlength{\unitlength}{1.5cm}\begin{picture}(8,2)\linethickness{0.4mm}\put(7.7,3){\large\sf{A}}\put(7.5,2){\sf{\large{135/16 cm}}}\put(7.7,1){\large\sf{B}}\put(9.3,0.7){\sf{\large{168/8 cm}}}\put(11.1,1){\large\sf{C}}\put(11.1,3){\large\sf{D}}\put(8,1){\line(1,0){3}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\end{picture}$

As we know that,

$\dag\;{\underline{\boxed{\bf{\pink{Perimeter = 2( Length + Breadth)}}}}}$

$\;\;\;\small\sf\star\; \underline{Put\;the\;GivEn\;values:-}$

$:\implies\sf 2( 33.6 + 22.5)$

$:\implies\sf 2(56.1)$

$:\implies{\underline{\boxed{\bf{\blue{2(112.2\;m)}}}}}$ ★

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★ Cost of fencing of one ground,

$:\implies\sf 112.2 \times \dfrac{21}{2}$

$:\implies\sf 112.2 \times 10$

$:\implies{\underline{\boxed{\bf{\orange{1122\;Rs}}}}}$ ★

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★ Cost of fencing it for 5 grounds,

$:\implies\sf 1122 \times 5$

$:\implies{\underline{\boxed{\bf{\orange{5610\;Rs}}}}}$ ★

$\dag\;\sf \underline{Hence,\;cost\;of\;fencing\;the\;ground\;is\; \bf{5610\;Rs}.}$

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Additional Information:-

★ Formula related to Rectangle -

⠀⠀⠀⠀✩ Area of Rectangle = l × b

⠀⠀⠀⠀✩ Perimeter of Rectangle = 2(l + b)

⠀⠀⠀⠀✩ Diagonal of Rectangle = $\sf \sqrt{w^2 + l^2}$

Where,

• l = Length of Rectangle

• b = Breadth of Rectangle

• w = Width of Rectangle

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