Math, asked by vismaireddy, 10 months ago

Armans age is three times his sons age.ten years ago he was five times his sons age.find their present age​

Answers

Answered by hariommaurya97
6

Son age be x

Arman age is 3x

ten years ago

son age x-10

arman age 3x -10

A.T.Q

5(x-10) = 3x -10

 5x -50 = 3x - 10

2x = 40

x =20

3x=60

son present age =20

arman present age = 60

hope it helps ❤️

Answered by Anonymous
47

Answer:

Given:

→ Arman's age is three times his sons age, Ten years ago he was five times his sons age.

Find:

→ Find their present ages.

Calculations:

→ Let us assume 'x' as the age of son and '3x' be the age of Arman.

→ Ten years ago the son age is 'x - 10' and Arman's age would be '3x - 10'.

→ 5 (x - 10) = 3x -10

→ 5x - 50 = 3x - 10

→ 2x = 40

x = 20

3x = 60

Therefore,

→ The present age of son = 20.

→ The present age of Arman's = 60.

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