Question

Armstrong ni. in java

Answer 1

 int a,b,d,e,f=0; 

Scanner g=new Scanner(System.in);

System.out.println("Enter number :");

e=g.nextInt();

d=e;

while(e>0)
{
a=e%10;
e=e/10;
f=f+a*a*a;
}

if(f==d)
{
System.out.println("Armstrong Number");
}
else
{
System.out.println("Not armstrong Number");
}}}