Army's please answer my questions I am having tes now
Answers
Answer:
Qn 9.
70 + a = 180 degree (linear pair)
a = 110 degree
60 + b = 180 degree (linear pair)
b = 120 degree
sum of the measure of all interior angle of a pentagon is 540 degree.
therefore,
120 + 110 + 30 + x + x = 540
2x = 280
x = 140
Qn. 10.
Let the measures of two adjacent angles, ∠A and ∠B, of parallelogram ABCD are in the ratio of 3:2.
Let ∠A = 3x and ∠B = 2x
We know that the sum of the measures of adjacent angles is 180º for a parallelogram.
∠A + ∠B = 180º
3x + 2x = 180º
5x = 180º
∠A = ∠C = 3x = 108º (Opposite angles)
∠B = ∠D = 2x = 72º (Opposite angles)
the measures of the angles of the parallelogram are 108º, 72º, 108º, and 72º.
Qn. 11
Each interior angle = 165
Exterior angle of polygon =180 − 165 =15
The sum of exterior angles of any polygon is 360
Number of sides of regular polygon = 360/15
= 24 sided polygon
I hope it will help you
Have a bangastic day dear
I purple you always
