Question

Aron is 5 years younger than his brother ron. After 4 years Ron's age will be twice of aron's. Find their present ages

Answer 1

Answer:

Present age of Ron = 6 years

Present age of Aaron = 1 year

Step-by-step explanation:

Given:

Aron is 5 years younger than Ron

After 4 years Ron's age will be twice of Aron's

To Find :

Find their present ages

Solution :

Let Ron’s present age be x

Then Aaron’s present age = x - 5

After 4 years

Ron’s age = x + 4

Aaron’s age = x - 5 + 4

According to the question; 

Ron will be twice as old as Aaron

Therefore, x + 4 = 2(x - 5 + 4) 

⇒ x + 4 = 2(x - 1) 

⇒ x + 4 = 2x - 2

⇒ x + 4 = 2x - 2

⇒ x - 2x = -2 - 4

⇒ -x = -6

⇒ x = 6

Therefore,

Aaron’s present age = x - 5 = 6 - 5 = 1

Therefore,

age of Ron = 6 years

age of Aaron = 1 year.

Answer 2

Given :

• Aron is 5 years younger than his brother ron.

• After 4 years Ron's age will be twice of aron's.

To find :

• Their present ages =?

Step-by-step explanation :

Let, the present age of Ron's be, x.

Then, the present age of Aron's be, x - 5.

After 4 years Ron's age = x + 4

After 4 years Aron's age = x - 5 + 4.

According to the question :

➮ x + 4 = 2 (x - 5 + 4)

➮ x + 4 = 2( x - 1)

➮ x + 4 = 2x - 2

➮ x - 2x = - 2 - 4

➮ - 1x = - 6

➮ x = 6.

Therefore, We got the value of, x = 6.

Hence,

The present age of Ron's, x = 6 years.

The present age of Aron's , x - 5 → 6 - 5 = 1 year.