Question

Around a circular park of radius 21m, there is circular road of uniform width 7m outside it. find the area of road with solution please

Answer 1

Area of circular Park =
$\pi \: r {}^{2}$
$22 \div 7 \times 21 \times 21 = 1386$
Area of park and road =
$22 \div 7 \times (21 + 7) \times (21 + 7) = 2464$
Area of road= area of park and road - area of park
$area \: of \: road = 2464 - 1386 \\ = 1078 \: m ^{2}$

Answer 2

Answer:

$\pi {r}^{2}$

Is the Formulae used

Step-by-step explanation:

22/7 x 28 x 28 = 2464 m² (Circle¹ outer circle)

22/7 x 21 x 21 = 1386 m² (Circle² inner circle)

(28 we got by adding 21 [radius of inner circle] and width of path which is 7m.)

2464m² - 1386m² = 1078m²

Thus, Area of the path is 1078m²

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