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If a polygon of 'n' sides has n(n-3) diagonals
. How many sides are there in a polygon
with 65 diagonals? Is there a polygon with 50 diagonals?
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The number of diagonals a polygon has is given by the formula n(n-3)/2. n(n-3) =18 => n^2 - 3n -18 = 0 => n = 6 , -3. Ignoring the negative value, n = 6. Hence the polygon has 6 sides (Hexagon).
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