Question

arpirta's present age is d years while annaya's is (d-6) years in ten years annay's age will be two thirds of arprita's find annay's present age

Answer 1

Answer:

• Annaya's present age is 2 years .

Step-by-step explanation:

Given that:

• Arpita's present age is d years while Annaya's is (d - 6) years.
• In 10 years Annaya's age will be two thirds Arpita's.

To Find:

• Annaya's present age.

Present ages of:

• Arpita = d years
• Annanya = (d - 6) years

After 10 years:

• Arpita's age = (d + 10) years
• Annanya's age = (d - 6 + 10) years

Finding the Annaya's present age:

According to the question.

⟶ 2/3 (d + 10) = (d - 6 + 10)

Cross multiplication.

⟶ 2(d + 10) = 3(d - 6 + 10)

⟶ 2d + 20 = 3d - 18 + 30

⟶ 2d - 3d = - 18 + 30 - 20

⟶ - d = - 8

⟶ d = 8

Annaya's present age = (d - 6) years

Annaya's present age = (8 - 6) years

Annaya's present age = 2 years

Answer 2

Given : Arpirta's present age is d years while Annaya's is (d-6) years & In ten years Annay's age will be two thirds of Arprita's .

Exigency To Find : Present age of Annay's .

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀Given that ,

⠀⠀⠀⠀⠀▪︎⠀⠀⠀Arpirta's present age is d years , while

⠀⠀⠀⠀⠀▪︎⠀⠀ Annaya's is (d-6) years

⠀⠀☆ AFTER 10 YEARS their ages :

⠀⠀⠀⠀⠀▪︎⠀⠀Arpita's age will be ( d + 10 ) years &

⠀⠀⠀⠀⠀▪︎⠀⠀Annay's age will be ( d - 6 + 10 ) years .

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\: \: According \: to\: the \: Question \::}}$

⠀⠀⠀⠀⠀━━━ In ten years Annay's age will be two thirds of Arprita's .

$\qquad \dashrightarrow \sf Annay's \:age_{( After \:10\:years \:)} = \: \dfrac{2}{3} \bigg( Arpita's \:age_{( After \:10\:years \:)}\bigg)\:\:$

$\qquad \dashrightarrow \sf (\: d - 6 + 10 \:)\:= \: \dfrac{2}{3} \bigg( d + 10 \bigg)\:\:$

$\qquad \dashrightarrow \sf \:3( d - 6 + 10) \:\:= \: 2 ( d + 10 )\:\:$

$\qquad \dashrightarrow \sf \:3d - 18 + 30 \:\:= \: 2 d + 20\:\:$

$\qquad \dashrightarrow \sf \:3d + 30 \:\:= \: 2 d + 20 + 18\:\:$

$\qquad \dashrightarrow \sf \:3d + 30 \:\:= \: 2 d + 38\:\:$

$\qquad \dashrightarrow \sf \:3d \:\:= \: 2 d + 38- 30\:\:$

$\qquad \dashrightarrow \sf \:3d \:\:= \: 2 d + 8 \:\:$

$\qquad \dashrightarrow \sf \:3d - 2d \:\:= \: 8 \:\:$

$\qquad \dashrightarrow \sf \:d \:\:= \: 8 \:\:$

$\qquad \dashrightarrow \pmb{\underline{\purple{\:d = 8\; yrs }} }\:\:\bigstar$

⠀⠀⠀⠀⠀▪︎⠀Here d denotes Present age of Arpita which is 8 years .

⠀⠀⠀⠀⠀AND,

⠀⠀⠀⠀⠀▪︎⠀Present of Annay will be ( d - 6 ) = ( 8 - 6) = 2 years .

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Hence,\:Present \:age\:of\:Annay \:is\:\bf{2 \:years}}}}$