Math, asked by fk3355527, 5 days ago

Arpit can fence a garden in 3hrs ,Ankur can do it in 5hrs and Akash takes 6hrs m to do the same. If they work together, in how many hours can they fence the garden ( in Inverse variations)​

Answers

Answered by tapaspani709
3

Ans . Arpit takes 3hrs to fence a garden.

Ankur takes 5hrs to fence a garden.

Aakash takes 6hrs to fence a garden.

a

First we have to take LCM of 3,5,6 which is 30.

So in 30hrs Arpit fence 30/3 = 10 gardens

Like that in 30hrs Ankur fence 30/5= 6 gardens

And Aakash in 30hrs fence 30/6= 5 gardens

Total Garden = 10+ 6+5 = 21

Total Hours = 30+ 30+ 30 = 90

21 garden takes 90hrs if they work together .

So They together fence that 1 garden in 90/21 = 4.28 hrs

So Ans is 4.28 hrs .

Answered by Johnsonmijo
1

Answer:

If Arpit, Ankur, and Akash can fence a garden in 3 hrs, 5 hrs, 6hrs respectively. Then they can complete the work together in 1.42 hours

Step-by-step explanation:

Let W be the total amount of work required to fence the garden

Given

Time Arpit requires to fence the garden = 3hrs

Amount of work done by Arpit in 1 hour = \frac{1}{3} of total work= \frac{1}{3}W

Time Ankur requires to fence the garden = 5hrs

Amount of work done by Ankur in 1 hour = \frac{1}{5} of total work= \frac{1}{5}W

Time Akash requires to fence the garden = 6hrs

Amount of work done by Akash in 1 hour = \frac{1}{6} of total work = \frac{1}{6}W

Amount of work done by Arpit, Ankur, and Akash in 1 hour

=\frac{1}{3}+\frac{1}{5}+\frac{1}{6} \\\\=\frac{1*10}{3*10} +\frac{1*6}{5*6} +\frac{1*5}{6*5} \\\\=\frac{10}{30} +\frac{6}{30} +\frac{5}{30} \\\\=\frac{21}{30} \\\\=\frac{7}{10}W

So 7/10 of total work is done in 1 hour

So total work W is done in \frac{1}{\frac{7}{10} } \\\\=\frac{10}{7} \\\\= 1.42

So, Arpit, Ankur, and Akash can complete the work together in 1.42 hours

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