Question

arrange 13by-28,-23by42, -4by7and'-9by14 in ascending order​

Answer 1

$\huge{\textsf\red{Answer:-}}$

$\red\mapsto\sf{ \frac{ - 9}{14}, \: \frac{13}{ - 28}, \: \frac{ - 4}{7} , \: \frac{ - 23}{42}}$

Answer 2

Question :

$\sf \small Arrange \frac{13}{ - 28}, \frac{ - 23}{42} , \frac{ - 4}{7} \: and \: \frac{ - 9}{14}$

Process :

First we need to observe that their is any any fraction which can be divisible then we are going to do the L.C.M of all the fractions and then we need to arrange them according to the given problem

Solution :

$\sf \leadsto\frac{ - 13}{28}, \frac{ - 23}{42} , \frac{ - 4}{7} \: and \: \frac{ - 9}{14}$

So there are no common factors for any of the fraction

By doing L.C.M we get

L.C.M = 84

$\sf \leadsto (\frac{- 13 \times 3}{28 \times 3} ),( \frac{ - 23 \times 2}{42 \times 2} ),( \frac{ - 4 \times 12}{7 \times 12} ), (\frac{ - 9 \times 6}{14 \times 6} )$

Now multiplying them we get

$\sf \leadsto\frac{ - 39}{84} , \frac{ - 46}{84} , \frac{ - 48}{84} , \frac{ - 54}{84}$

Now it would be easier as the denominators are common

Hence, arranging in ascending orders we get

$\sf \leadsto \frac{ - 54}{84} < \frac{ - 48}{54} < \frac{ - 46}{84} < \frac{ - 39}{84}$

Therefore the original fractions are

$\sf \leadsto\frac{ - 9}{14} < \frac{ - 4}{7} < \frac{ - 23}{42} < \frac{ - 13}{28}$