Chemistry, asked by Faheem1011, 3 months ago

Arrange 2,2-Dimethylbutane, 3-Methylpentane and n-Hexane in the ascending order of their boiling point, also explain the basis for your order.

Answers

Answered by mayankdagurexpert
0

Explanation:

Explanation:</p><p>More is the number of carbon atoms attached linearly or in the form of a long chain then more will be the boiling point of that compound.</p><p>Whereas if carbon atoms are attached through branching then there will be decrease in the boiling point of the compound.</p><p>The structure of n-butane is CH_{3}CH_{2}CH_{2}CH_{3}CH3CH2CH2CH3 .</p><p>The structure of 2 methyl butane is CH_{3}CH(CH_{3})CH_{2}CH_{3}CH3CH(CH3)CH2CH3 .</p><p>The structure of n-pentane is CH_{3}CH_{2}CH_{2}CH_{2}CH_{3}CH3CH2CH2CH2CH3 .</p><p>The structure of 2,2dimethypropane is C(CH_{3})_{4}C(CH3)4 .</p><p>Thus, we can conclude that boiling points in decreasing order are as follows.</p><p>    n-pentane &gt; n-butane &gt; 2 methyl butane &gt; 2,2dimethypropane</p><p></p><p>

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