Question

Arrange √2, ∛4, ∜5 and ∜3 in ascending order​

Answer 1

fdIb vjg l do do sul drunk h to jo hi to nhi

Answer 2

Answer:

∜3 < √2 < ∜5 < ∛4  

Step-by-step explanation:

√2, ∛4, ∜5 and ∜3

LCM of 2,3,4 = 12

√2 = $\sqrt[2\times6]{2^6}$ = $\sqrt[12]{64}$

∛4 = $\sqrt[3\times4]{4^4}$ = $\sqrt[12]{256}$

∜5 = $\sqrt[4\times3]{5^3}$ = $\sqrt[12]{125}$

∜3 = $\sqrt[4\times3]{3^3}$ = $\sqrt[12]{27}$

clearly,

in ascending order,

$\sqrt[12]{27}$  <  $\sqrt[12]{64}$   <    $\sqrt[12]{125}$   <  $\sqrt[12]{256}$

ie., ∜3 < √2 < ∜5 < ∛4