Question

Arrange -5/9,7/12,-2/3,11/18 in the ascending order of their magnitudes. also find the difference between the largest and the smallest of these rational numbers. express this difference as a decimal fraction correct to one decimal place

Answer 1

-2/3<-5/9<7/12<11/18
11/18-(-2/3) = 11/18+2/3 = 23/18 = 1.278.... = 1.3

Answer 2

Our required answer is 1.3

Step-by-step explanation:

Given,

$\frac{-5}{9}, \frac{7}{12}, \frac{-2}{3}, \frac{11}{18}$

First, converting the fractions into like fractions.

LCM of 9, 12, 3 and 18 is 36.

$=> \frac{-5\times 4}{9\times 4}, \frac{7\times 3}{12\times 3}, \frac{-2\times 12}{3\times 12}, \frac{11\times 2}{18\times 2}\\\\=> \frac{-20}{36}, \frac{21}{36}, \frac{-24}{36}, \frac{22}{36}$

As denominators of the fractions are equal.

Compare the numerators.

As -24 < -20 < 21 < 22,

$=>\frac{-24}{36}, \frac{-20}{36}, \frac{21}{36}, \frac{22}{36}$

The ascending order of rational numbers is $\frac{-2}{3}, \frac{-5}{9}, \frac{7}{12}, \frac{11}{18}$

Largest of the rational numbers = $\frac{11}{18}$

Smallest of the rational numbers = $\frac{-2}{3}$

Difference

$\frac{11}{18} - (\frac{-2}{3})\\\\= \frac{11}{18} + \frac{2}{3}\\\\= \frac{11+12}{18}\\\\= \frac{23}{18}$

= 1.277777

≈ 1.3

Hence, our required answer is 1.3