Question

Arrange an 8-, 12-, and 16-Ω resistor in a combination that has a total resistance of 8.89 Ω

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

arrange 8,12 in series and then resultant with 16 in parallel

Explanation:

8+12=20

1/r=1/20+1/16

=9/80

r=80/9=8.89 ohms