Arrange: Be,Li,C,B,N,O,F in increasing metallic character
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Hey dear here is your answer!!!!!
Fluorine is least metallic
Then F(fluorine)
Then O(oxygen)
Then N(nitrogen)
Then C(carbon)
Then B(boron)
Then Be(beryllium)
Then Li(lithium)
Lithium is the most mettalic
Hope it helps u....☺️☺️
Fluorine is least metallic
Then F(fluorine)
Then O(oxygen)
Then N(nitrogen)
Then C(carbon)
Then B(boron)
Then Be(beryllium)
Then Li(lithium)
Lithium is the most mettalic
Hope it helps u....☺️☺️
helpme10:
i edited
Answered by
1
The increasing metallic character is as follows-
F<O<N<C<B<Be<Li.
- Metals are defined as species that easily release electrons and form cations. Thus an element that can easily release an electron has a high metallic character.
- As we move left to right in a periodic table the size of the atom decreases hence the electron releasing tendency decreases so, the metallic character also decreases.
- Hence the increasing metallic character is as follows-
- F<O<N<C<B<Be<Li.
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