Chemistry, asked by Kunjalbabbar970, 1 year ago

Arrange: Be,Li,C,B,N,O,F in increasing metallic character

Answers

Answered by helpme10
112
Hey dear here is your answer!!!!!

Fluorine is least metallic

Then F(fluorine)
Then O(oxygen)
Then N(nitrogen)
Then C(carbon)
Then B(boron)
Then Be(beryllium)
Then Li(lithium)

Lithium is the most mettalic

Hope it helps u....☺️☺️

helpme10: i edited
gauransh9696: ✌️✌️
gauransh9696: Mate Fluorine is least metallic nd not least reactive I think
helpme10: ooohooo
helpme10: any other mistake
gauransh9696: Koi nae It happens!!!
helpme10: yes
gauransh9696: Plz don't mind that I asked you to crct it
helpme10: no no never
helpme10: instead i thanks u
Answered by qwmagpies
1

The increasing metallic character is as follows-

F<O<N<C<B<Be<Li.

  • Metals are defined as species that easily release electrons and form cations. Thus an element that can easily release an electron has a high metallic character.
  • As we move left to right in a periodic table the size of the atom decreases hence the electron releasing tendency decreases so, the metallic character also decreases.
  • Hence the increasing metallic character is as follows-
  • F<O<N<C<B<Be<Li.
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