Chemistry, asked by faizanbhat6808, 9 months ago

Arrange Ch4 Becl2 Nh3 in decreasing order of bond angle

Answers

Answered by nsailikhitha79
0

Answer:Becl2> Ch4> Nh3

Explanation:

Becl2 is sp hybridization and the bond angle is  180 degrees.

Ch4 is sp3  hybridization and the bond angle is 109 degrees.

Nh3 the hybridization is sp3 and the bond angle is (less than)  <109 degrees because presence of lone pair on Nitrogen atom.

                               ( Bond angle is inversely proportional to lone pair. )

Answered by Anonymous
0

Answer:BeCl2>CH4>NH3

Explanation:

CH4 has bond angle of 109.5 and NH3 has 107.6 . In CH4 there is hybridization of sp3 where only four bonding electron pair are present whereas in NH3, despite being sp3 hybridized, have three bonding electron pair and one lone pair . BeCl2 is linear in shape. In case the beryllium atom formed bonds using pure orbitals, the shape of the molecule might have been angular. ... These half filled Sp-orbitals form two à Æ' bonds with two 'Cl' atoms and hence this leads to the linear shape of Thus BeCl2 with the bond angle of 180 degree

                hope this helps...

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