Question

Arrange in ascending order :3root 2,2root4,4root3
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Answer 1

Answer:

Step-by-step explanation:

$\sqrt[3]{2}, \sqrt{4}, \sqrt[4]{3}$

lets take LCM of powers to get a common root,

LCM(3, 2, 4) = 12

∴ Numbers will be ⇒

    $\sqrt[12]{2^{4}}\\\sqrt[12]{4^{6}}\\\sqrt[12]{3^{3}}$

⇒

    $\sqrt[12]{16} \\\sqrt[12]{4096} \\\sqrt[12]{27}$

∴ Order is ⇒

   $\sqrt[3]{2}$ < $\sqrt[4]{3}$ < $\sqrt{4}$