Question

Arrange in ascending order:
4√3,2√27,5 and √75

Answer 1

Answer:

4√3<√75<2√27

Step-by-step explanation:

Thank you

Answer 2

The numbers in order are 5, 4√3, √75, and 2√27.

Given:

4√3, 2√27, 5, and √75

To find:

The numbers are arranged in ascending order

Solution:

We will convert the given terms into roots and arrange them accordingly.

The given terms are-

4√3, 2√27, 5, and √75

We can write them as follows-

4√3=√(4×4×3)=√48

2√27=√(2×2×27)=√108

5=√(5×5)=√25

The terms are √48, √108, √25, and √75.

We will now arrange these in ascending order.

=√25, √48, √75, √108

= 5, 4√3, √75, 2√27

Therefore, the numbers in order are 5, 4√3, √75, and 2√27.

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