Question

arrange in ascending order-
6 root 2, 2 root 6, root 12, 4 root 3

Answer 1

Answer:

root 12 < 2root6 < 4root3 < 6root2

Step-by-step explanation:

$6root2 \\ = 6 \sqrt{2} \\ = \sqrt{6 \times 6 \times 2} \\ = \sqrt{72}$

=root72

$2root6 \\ = 2 \sqrt{6} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{2 \times 2 \times 6} \\ = \sqrt{24}$

=root24

$root12 \\ = \sqrt{12}$

=root12

$4root3 \\ = 4 \sqrt{3} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{4 \times 4 \times 3} \\ = \sqrt{48}$

=root48

Answer 2

Answer:

• hope it is helpful