Arrange the elements of the second and third period in increasing order of their atomic size.
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Answer:
The following are the ionization energies for the elements in the second period:
Lithium - 520
Beryllium - 900
Boron - 801
Carbon - 1087
Nitrogen - 1402
Oxygen - 1314
Fluorine - 1681
Neon - 2081
Hence, arranging them according to increasing ionization energy, we get:
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Explanation:
Second period: Neon > Fluorine > Oxygen > Nitrogen > Carbon > Boron > Beryllium > Lithium Third Period: Argon> Chlorine > Sulphur > Phosphorus > Silicon > Aluminum >Magnesium
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