arrange the following according to stability
CH3CH2 , (CH3)3C , (CH3)2CH
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acc to Sn1 reaction
Ch3ch2 < ch3ch<(ch3)3c
acc to sn2 the order would be reversed..!
Ch3ch2 < ch3ch<(ch3)3c
acc to sn2 the order would be reversed..!
Answered by
18
Hey dear,
● Answer -
Increasing order of stability of carbocations -
CH3CH2• < (CH3)2CH• < (CH3)3C•
● Explanation -
- As you may know stability of carbocations follows following trend -
methyl < 1° < 2° < 3°
Given carbocations -
(CH3)3C• => 3° carbocation
(CH3)2CH• => 2° carbocation
CH3CH2• => 1° carbocation
Therefore, increasing order of stability of carbocations -
CH3CH2•(1°) < (CH3)2CH•(2°) < (CH3)3C•(3°)
Hope this solved your queries.
● Answer -
Increasing order of stability of carbocations -
CH3CH2• < (CH3)2CH• < (CH3)3C•
● Explanation -
- As you may know stability of carbocations follows following trend -
methyl < 1° < 2° < 3°
Given carbocations -
(CH3)3C• => 3° carbocation
(CH3)2CH• => 2° carbocation
CH3CH2• => 1° carbocation
Therefore, increasing order of stability of carbocations -
CH3CH2•(1°) < (CH3)2CH•(2°) < (CH3)3C•(3°)
Hope this solved your queries.
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