Chemistry, asked by arbazbaddi7204, 11 months ago

Arrange the following alcohols in order of their decreasing
tendency to form carbocation.
C₆H₅CH₂OH
(a) I > II > III > IV (b) IV > III > I > II (c)
IV > III > II > I (d) II > I > IV > III

Answers

Answered by Anonymous
3

tendency to form carbocation

OPTION B IS CORRECT ANSWER

Answered by brokendreams
3

IV > III > II > I is the trend of carboncation formation.

Explanation:

  • The carboncation is a reaction intermediate that involves a positive charge on a carbon atom.
  • This carboncation formation is effected by the stability of the carbocation.
  • More stable carbocations are readily formed than the less stable ones.
  • In case of the benzyl alcohol, its supported by resonance and the charge is widely dispersed in the molecule.
  • So it will be highly preferred.
  • In case of option 3, the carbocation is 2° where it's supported by positive inductive effect of the methyl groups.
  • In case of option 1 and 2, both are rendered unstable by the negative inductive effect of the fluorine atoms.
  • But the effect is rendered through 2 carbon atoms in option 2 and 1 carbon atom in carbon 1.
  • So option 1 is more unstable than option 2.
  • So the trend is IV > III > II > I.

For more information about carbocations,

https://brainly.in/question/8838752

the decreasing order of stability of following cations is

ethane carbocation

ethene carbocation

ethyne carbocation

ch3-c+≈o

https://brainly.in/question/7425761

what is carbocation ? - Brainly.in

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