Arrange the following as per the instructions given in the brackets:
(1) Cs, Na, Li, K, Rb (increasing order of metallic character).
(2) Mg, Cl, Na, S, Si (decreasing order of atomic size).
(3) Na, K, Cl, S, Si (increasing order ionization energy)
(4) Cl, F, Br, I (increasing order of electron affinity)
(5) Cs, Na, Li, K, Rb (decreasing electronegativity)
(6) K, Pb, Ca, Zn (increasing reactivity)
(7) Li, K, Na, H (decreasing order of their potential ionisation)
Answers
Answer:
1. Explanation: As incresing order of metallic character means ascending order , Na, K, Rb, Cs. As decreasing order of atomic size means descending order So, Na, Mg, Si, S, Cl.
2. As decreasing order of atomic size means descending order So, Na, Mg, Si, S, Cl. As increasing order of ionization energy means ascending order So, K, Na, Si, S, Cl, As increasing order of electron affinity means ascending order so, I, Br, F, Cl.
3. As decreasing order of atomic size means descending order So, Na, Mg, Si, S, Cl. As increasing order of ionization energy means ascending order So, K, Na, Si, S, Cl, As increasing order of electron affinity means ascending order so, I, Br, F, Cl.
4. Since the atomic size increases down the group, electron affinity generally decreases (At < I < Br < F < Cl). An electron will not be as attracted to the nucleus, resulting in a low electron affinity. ... This can be explained by the small size of fluorine, compared to chlorine
5. As we move from top to bottom in group the electron-affinity will be decreased, because the atomic radius will be increased so distance from outer electrons to the nucleus will be increased,so the electrons will be difficultly added Li, Na, K, Rb, Cs are IA group elements from Li to Rb the electronegativity will be decreased.so, the correct answer is Cs, Rb, k, Na ,Li
6. pb, Zn ,Ca, K( increasing reactivity)
7. As we move from top to bottom in the group, the ionization energy will be decreased, because the atomic radius will be increased so the removal electron will be easy. Li, Na, K are IA group elements of the periodic table. ... Therefore, the correct order of ionization energy is Li>Na>K.
hope this will helpful for you
The following are arranged as per instructions given in the brackets:
(a) Mg, Cl. Na, S, Si (decreasing order of atomic)
Na>Mg>S>Si>Cl
(b) Cs, Na, Li, K, Rb (increasing metallic character)
Li<Na<K<Rb<Cs
(c) Na, K, CI, S. Si increasing ionisation potential)
K<Na<Si<S<CI
(d) CI, F. Br, I (increasing electron affinity)
I<Br<CI<F
(e) Cs. Na, Li, K, Rb (decreasing electronegativity)
Li>Na>K>Rb>Cs
(f) K, Pb, Ca, Zn (increasing reactivity)
Pb<Zn<Ca<K
(g) Li, K, Na, H (decreasing order of their potential ionisation)
Li<Na<K<H