Arrange the following carbanions in decreasing order of stability:
CH2=CH
(P)
Ph-CH2
CH2=CH-CH2
(2)
(R)
(A) P>Q>R>S
(D) Q> S >R>P
(B) S>Q>P>R
(C) S>Q>R>P
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Answer:
b is the right answer for this question
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