Chemistry, asked by deeppatel36, 1 month ago

Arrange the following carbanions in decreasinng order of their
stability:
(0) HC =0
(II) CH3--0
(III) H2C = CH
(IV) CH3 - CH2

Answers

Answered by nagale1955

0

Answer:

1HC=O

2CH3=0

3H2C=CH

4CH3=CH2

Answered by opraiden4

0

Answer:

HC=0

H2C=CH

CH3--0

CH3-CH2

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