Question

arrange the following carboanion in increasing order of their stability.

(CH)3C, CH3CH2 ,CH3 ,(CH3)2CH

Answer 1

The answer is in Attachment

Answer 2

The stability order is-

$CH_3<CH_3CH_2<(CH_3)_2CH<(CH_3)_3C$

• A tertiary carbanion is more than a secondary carboanion and a primary carbanion.
• Again as the number of a methyl group increases in a carbanion, the carbanion become more stable.
• Thus in the case of methyl carbanion, it is primary so least stable.
• Ethyl carbanion is also 1° carbanion but it has one methyl group so, moderately stable.
• Propyl carbanion is 2° so stable.
• A tertiary carbanion is 3° so, highly stable.
• Thus the stability order will be-
• $CH_3<CH_3CH_2<(CH_3)_2CH<(CH_3)_3C$