Question

. Arrange the following complexes in the decreasing order of their electrical conductivity 1.[Co(NH₃)₄Cl]Cl 2.K₂[PtCl₆] 3.[Ni(NH₃)₄Cl₂] 4.K₄[Fe(CN)₆] * A.4>2>1>3 B.1>2>3>4 C.3>4>2>1 D.4>3>2>1

Answer 1

Complexes in decreasing order of electrical conductivity - A.4>2>1>3

Electrical conductivity refers to movement of charge across the material or solution. The conductivity of solution becomes possible due to presence of ions.

Hence, large the number of ions, larger will be the electrical conductivity of solution.

In the options given in question,

[Co(NH₃)₄Cl]Cl will ionise into two ions. K₂[PtCl₆] will ionise into three ions.[Ni(NH₃))₄Cl₂] will not ionise into ions. K₄[Fe(CN)₆] will ionise into five ions.

Thus, decreasing order of electrical conductivity will be - 4>2>1>3.