Question

arrange the following data in the form of an exclusive frequency distribution:30-34, 35-39, 40-44, 45-49, 50-54, 55-59 frequency are 7,9,13,6,3,10 respectively




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Answer 1

Answer:

ms562526 d633636 +568+25946+

558256

Step-by-step explanation:

Answer 2

Solution :-

The class intervals given are not continuous so, first we will make it continuous by subtracting 0.5 from the lower limit of each class interval and adding 0.5 to the the upper limit of each class interval. After that we have to find the class marks (mid values) of each interval, that is (lower limit + upper limit)/2. The points of the frequency polygon for each class interval is (class marks, frequency).

Class Interval Class Marks (Mid Values) Frequency

24.5 - 29.5 27 5

29.5 - 34.5 32 15

34.5 - 39.5 37 23

39.5 - 44.5 42 20

44.5 - 49.5 47 10

49.5 - 54.5 52 7