Question

Arrange the following descending order 2/7 , 11/25 , 9/14 , 19/26.

Answer 1

Answer:

descending order = 19/26, 9/14, 11/25, 2/7

Step-by-step explanation:

L.C.M. of 7,25,26.14 = 4550

2/7 = 2/7 × 650/650 = 1300/4550

11/25 = 11/25 × 182/182 = 2002/4550

9/14 = 9/14 × 325/325 = 2925/4550

19/26 = 19/26 × 175/175 = 3325/4550

descending order = 3325/4550, 2925/4550, 2002/4550, 1300/4550

=>19/26, 9/14, 11/25, 2/7

Hope this helps

Please mark as branliest

Answer 2

Answer :-

• The rational numbers arranged in descending order are :- 19/26, 9/14, 11/25 and 2/7.

What to do :-

• Arrange the following rational numbers in descending order :- 2/7, 11/25, 9/14, 19/26.

Step-by-step explanation :-

• Here, we are asked to arrange some rational numbers in descending order. For comparing these numbers, we have to make their denominator same. So let's find the LCM of their denominators [7, 25, 14 and 26].

By prime factorisation method, we see that the LCM of 7, 14, 25 and 26 is 63700.

-----------------------------------------

Now, the given numbers can also be written as :-

$\implies\sf{\dfrac{2}{7} = \dfrac{2 \times 9100}{7 \times 9100} = \dfrac{18200}{63700}}$

$\implies\sf{\dfrac{11}{25} = \dfrac{11 \times 2548}{25 \times 2548} = \dfrac{28028}{63700}}$

$\implies\sf{\dfrac{9}{14} = \dfrac{9 \times 4550}{14 \times 4550} = \dfrac{40950}{63700}}$

$\implies\sf{\dfrac{19}{26} = \dfrac{19 \times 2450}{26 \times 2450} = \dfrac{46550}{63700}}$

We see that :-

$\bf \dfrac{46550}{63700} < \dfrac{40950}{63700} < \dfrac{28028}{63700} < \dfrac{18200}{63700}$

Hence :-

• The rational numbers arranged in descending order are :- 19/26, 9/14, 11/25 and 2/7.

________________________________