Chemistry, asked by msneha1101, 11 months ago

Arrange the following dicarbon species in order of their bond length :
C2, C2-, C2*2-

Answers

Answered by abhilasha098
12

Answer:

c2>c2->c2-2

Explanation:

see bond length is inversely proportinal to bond order that is higher the bond order lower will be the bond length and their bond order are as follows

c2=2

c2- = 2.5

c2-2= 3

Answered by PravinRatta
2

The order of bond length of the given dicarbon species are: C_{2} >{C_{2} ^{-} >{C_{2} ^{2-}

We can find out the order of bond length using bond order.

  • Bond order is the number of Chemical bonds formed between a pair of atoms. It indicates the stability of a bond.
  • Bond order is inversely proportional to the bond length.
  • The bond order of C_{2} is 2.
  • The bond order of {C_{2} ^{-} is 2.5.
  • The bond order of {C_{2} ^{2-} is 3.

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