Arrange the following elements in the decreasing order of their atomic radii. B, O, Li, Be, C, N
Answers
Li , Be , B, C, N , O
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Answer:
Decreasing order of atomic radii:
Li > Be > B > C > N > O > F
Explanation:
Atomic radius:
The distance between the center of the nucleus and the outermost shell of an atom is called the atomic radius.
Trends in atomic radii:
In a group, the atomic radius will increase because of the addition of shells as we pass from one period to another. Across a period the atomic radius decreases because the number of shells continues to be equal even as the nuclear charge will increase. This results in the pulling of electrons from the outermost shell closer to the nucleus thereby reducing the radius.
Exception:
There is only one exception withinside the fashion of atomic radii along the period. In a regular fashion, the atomic radius will increase over a period but the atomic radius of noble gases is greater than the adjoining halogen atom. This is due to the fact noble gas atoms are held collectively with the aid of using van der Waal forces (which can be weaker and as a result, the atoms are apart from every other) even as the halogen atoms are bound together with the aid of using covalent bonds which can be much stronger than the van der Waal forces and as a result held the atoms closer.
Therefore the given elements belong to the 2nd period, and as the atomic radius decreases along the period.
the correct order will be Li > Be > B > C > N > O > F.
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