Question

. Arrange the following elements in the decreasing order of number of atoms.

1g Au (197)

• 1g Na (23)

• 1g Li (7)

• 1g C12 (71)​

Answer 1

Answer:

(i) Gram atomic mass of Au= 197 g

Or

197g of Au contains = 6.022 x 1023

Therefore 1gm of Au contains = 6.022 x 1023/197*1 = 3.06 x 1021 atoms

(ii) Gram atomic mass of Na = 23 g

Or

23 g of Na contains atoms = 6.022x 1023

Or

1gm of Na contains atoms = 6.022x1023 /23 *1 = 26.2 x1021 atoms

(iii) Gram atomic mass of Li = 7

Or

7g of Li contains atoms = 6.022 x 1023

Or

1g of Li contains atoms = 6.022 x 1023/7 *1= 86.0 x 1021 atoms

(iv) Gram atomic mass of Cl = 71 Or 71g of Cl contains atoms = 6.022x1023

Or

1 g of Cl contains atoms = 6.022x1023 /71 * 1= 8.48 x 1021 atoms

Bro arrange this you will get the answer