Question

arrange the following h-h,d-d and f-f in increasing bond dissociation enthalpy

Answer 1

Heya,
Bond dissociation enthalpy. The order of increasing bond dissociation enthalpy is:F-F<H-H<D-D
Reason: Since D has a smaller size than H, therefore D-D bond has the highest bond dissociation enthalpy followed by H – H. On the other hand, F – F bond has minimum dissociation enthalpy because of repulsion between lone pairs of F and bond pair.
____________________Hope helped:)

Answer 2

Increasing bond dissociation enthalpy will be F-F < D-D < H-H . Since h has the smallest size it’s bond dissociation enthalpy is highest