Question

arrange the following in descending order 3√2 , 4√5 , 6√7 and 12√3

Answer 1

Step-by-step explanation:

Explanation

We are given 4 numbers which are having roots , and we need to arrange them in descending order

Procedure

Now , since all the 4 numbers contain roots, the best way to compare the numbers is to square the given numbers

(1) (3root2)^2 = 18

(2) (4root5)^2 = 80

(3) (6root7)^2= 252

(4) (12root3)^2=432

It is pretty evident now that 12root3 is the greatest number and the least is 3root2

The descending order is as follows

12root3> 6root7>4root5> 3root2

Answer 2

Answer:

The given numbers arranged in descending order are 12√3, 6√7, 4√5, 3√2.

Step-by-step explanation:

The given numbers are 3√2, 4√5, 6√7, and 12√3.

We have to arrange them in descending order.

Since all the terms have roots, we rationalize the numbers by squaring them.

1. First term: 3√2 = (3√2)² = 9×2 = 18
2. Second term: 4√5 = (4√5)² = 16×5 = 80
3. Third term: 6√7 = (6√7)² = 36×7 = 252
4. Fourth term: 12√3 = (12√3)² = 144×3 = 432

As we can see, the largest number is 432 and the smallest number is 18. Arranging these squares in descending order, we get 432, 252, 80, 18.

Substituting the original values of these numbers, we get 12√3, 6√7, 4√5, 3√2.

Therefore, the descending order of the given numbers is 12√3, 6√7, 4√5, 3√2.

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