Question

arrange the following in descending order 5/2, 3/2, 7/2, 9/5, 9/8


pls answer fast!!!​

Answer 1

Step-by-step explanation:

descending order 5/2, 3/2, 7/2, 9/5, 9/8=

7/2,5/2,9/5,3/2,9/8

Answer 2

Answer:

Required answer is $\frac{7}{2} > \frac{5}{2} > \frac{9}{5} > \frac{3}{2} > \frac{9}{8}$

Step-by-step explanation:

Here given five fractions are $\frac{5}{2} , \frac{3}{2} , \frac{7}{2} , \frac{9}{5} , \frac{9}{8}$

We want to arrange all fractions in descending order.

Denominators are 2,2,2,5,8.

We are finding LCM of all denominators.

We know,

LCM means Lowest Common Multiples.

By prime factorisation,

$2 = 2 \times 1 \\ 5 = 5 \times 1 \\ 8 = 2 \times 2 \times 2 \times 1$

Lowest common multiple s of 2,5 and 8 $= (2 \times 5 \times 2 \times 2) = 40$

So,LCM of 2,5,8 are 40.

For the fraction $\frac{5}{2}$,

We are multiplying denominator and numerator by 20 and get

$\frac{5 \times 20}{2 \times 20} = \frac{100}{40}$

For the fraction $\frac{3}{2}$,

We are multiplying denominator and numerator by 20 and get $\frac{3 \times 20}{2 \times 20} = \frac{60}{40}$

For the fraction $\frac{7}{2}$,

We are multiplying denominator and numerator by 20 and get $\frac{7 \times 20}{2 \times 20} = \frac{140}{40}$

For the fraction $\frac{9}{5}$,

We are multiplying denominator and numerator by 8 and get,

$\frac{9 \times 8}{5 \times 8} \\ = \frac{72}{40}$

For the fraction $\frac{9}{8}$,

We are multiplying denominator and numerator by 5 and get,

$\frac{9 \times 5}{8 \times 5} \\ = \frac{45}{40}$

It is clear that,

$\frac{140}{40} > \frac{100}{40} > \frac{72}{40} > \frac{60}{40} > \frac{45}{40}$

So,

$\frac{7}{2} > \frac{5}{2} > \frac{9}{5} > \frac{3}{2} > \frac{9}{8}$

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