Math, asked by harshsalunke71, 1 year ago

Arrange the following in descending order of magnitude : 8√90,4√10,√6

Answers

Answered by Anonymous
395
Hi friend, Here is the required answer:-

8√90= 8√ 3×3×5×2= 8×3√10= 24√10= 75.89

4√10= 12.64

√6= 2.44

So, the descending order is 8√90> 4√10>√6.

Hope this helps you...
Answered by skyfall63
230

The descending order of magnitudes is:  \sqrt{6} ; \sqrt[4]{10} ; \sqrt[8]{90}

Step-by-step explanation:

The descending order is arrangement of number in decreasing order.

Let us take first number,

\sqrt[8]{90}=90^{1 / 8}

The value of the above number is,

\Rightarrow \sqrt[8]{90}=1.75

Let us take second number,

\sqrt[4]{10}=10^{1 / 4}

The value of the above number is,

\Rightarrow \sqrt[4]{10}=1.77

Let us take third number,

\sqrt{6}=6^{1 / 2}

The value of the above number is,

\Rightarrow \sqrt{6}=2.44

Now considering, the values of the number and arranging it in descending order, we get,

2.44, 1.77, 1.75

Now, we can arrange the given number in descending order, we get,

\sqrt{6} ; \sqrt[4]{10} ; \sqrt[8]{90}

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