Question

Arrange the following in increasing order of pKa values :
CH3COOH ,ClCH2COOH,Cl2CHCOOH,Cl3CCOOH​

Answer 1

Answer:

CH3COOH<ClCH2COOH<Cl2CHCOOH<Cl3CCOOH

Answer 2

Given compounds are arranged in increasing order of $pK_{a}$ values is as follows.

  $CH_{3}COOH$ < $ClCH_{2}COOH$ < $Cl_{2}CHCOOH$ < $Cl_{3}CCOOH$​

Explanation:

More easily a compound is able to lose a hydrogen ion more acidic it will be in nature. And then, more will be the value of its acidic constant, that is, $K_{a}$.

In $Cl_{3}C-COOH$ there are three electronegative chlorine atoms are attached. As a result, electrons are pulled more towards the chlorine atoms. Therefore, it is easy for the compound to lose a hydrogen ion as it is weakly attached.

This means that more is the number of electronegative atoms attached in a compound more will be the dissociation of hydrogen ions. And, more is the value of $K_{a}$, lesser will be the value of $pK_{a}$.

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