Question

Arrange the following in increasing order of property specified:

i. triethylamine, ethanamine, diethylethanamine (solubility in water)

ii. C4H9NH2, C2H5N(CH3)2 , (C2H5)2NH (boiling point)

iii. Ethanamine, N-Ethyl ethanamine, N,N-Diethyl ehanamine (Basic strength)​

Answer 1

Ethylamine when added to water forms intermolecular H−bonds with water. And therefore it is most soluble in water. 

Diethyl amine having bigger alkyl chain forms weaker intermolecular hydrogen bonds. 

But aniline does not form H−bond with water to a very large extent due to the presence of a large hydrophobic −C6H5 group. Hence, aniline has least solubility in water. 

Hence the order of solubility is iii>ii>i

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Answer 2

Answer:

3 2 1

Explanation:

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