Chemistry, asked by uday4144, 1 year ago

Arrange the following in increasing oxidation number of iodine: I₂, HI, HIO₄, IC1

Answers

Answered by renukasingh05011979
10

Answer:

HI < I2< ICI < HIO4; O.N. of I in I­2 = 0, HI = - 1, ICI = + 1, HIO4 = + 7.

I Hope It Will Help!

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