Question

Arrange the following in order of increasing property indicated: (1) HCHO, CH3COCH3, CH3CH2CHO, C6H5CHO (toward HCN) (2) CH3CHO, CH3COCH3, CH3COOH, CH3OCH3: (boiling point)​

Answer 1

Answer:

All these compounds have comparable molecular masses, CH

3

CH

2

OH undergo extensive intermolecular h-bonding, thus having the highest boiling point.

CH

3

CH

2

CH

3

have weak vander waals forces thus lowest boiling point.

And in CH

3

CHO there are more dipole-dipole interactions than CH

3

OCH

3

, thus having a greater boiling point.

CH 3CH2CH 3<CH 3OCH 3 <CH 3CHO<CH 3CH 2OH

Mark me as brainliest

Explanation:

CH 3CH2CH 3<CH 3OCH 3 <CH 3CHO<CH 3CH 2OH