Question

arrange the following in the decreasing order of Bond angle
c2h2 bf3 ccl4​

Answer 1

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 Bond angles in given compounds:

1. In C₂H₂ the bond angle is 180°
2. In BF₃ the bond angle is 120

    3. In CCl₄ the bond angle is approx. 109.4°

So, the decreasing order of bond angle is

                C₂H₂ ,BF ₃,CCl₄

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Answer 2

Answer:

Bond angles in the following compounds:

The bond angle in $C_{2} H_{2}$ is 180°.

The bond angle in $BF_{3}$ is 120 3.

The bond angle in $CCl_{4}$ is approximately 109.4°.

Hence, the bond angle is listed in decreasing order by

$C_{2} H_{2} , BF_{3}, CCl_{4}$.

Additional Information:

• A complex molecule's or ion's bond angle is the angle between the two bonds, or the angle between two orbitals that contain bonding electron pairs surrounding the central atom.
• It is computed using a spectroscopic approach and expressed in degrees. A bond angle is the arc formed by two covalent bonds that originate from the same atom.
• The geometric angle created by any two contiguous covalent bonds is referred to as the bond angle.

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