Question

Arrange the following in the order of increaing oxidation number of N :N3H,NH3,NO2,NO,N2O3,N2O5

Answer 1

Answer:

NH3,N3H,NO,N203,NO2,N2O5

Explanation:

a. NH3,

The oxidation number for hydrogen is +1

thus, N+3=0

N=-3

b. N3H,

3N+1=0

3N=-1

N=-1/3

c. NO,

the oxidation number for oxygen is -2

thus N-2=0

N=+2

d. N203

2N+3(-2)=0

2N-6=0

2N=6

N=+3

e. NO2

N+2(-2)=0

N-4=0

N=+4

f. N205

2N+5(-2)=0

2N-10=0

2N=10

N=+5

(the reason for equating with 0 is because all the compounds are neutral.)

Answer 2

Answer:

answer as follows

Explanation:

NO

NO2

N2O3

N2O5

N3H

NH3