Chemistry, asked by Akshikiski6560, 10 months ago

Arrange the following ions in the order of decreasing X – O
bond length, where X is the central atom in
(a) ClO₄⁻ ,SO₄²⁻ ,PO₄³⁻ ,SiO₄⁻ - - - -
(b) SiO₄⁴⁻ ,PO₄³⁻ ,SO₄²⁻ ,ClO₄⁻ - - - -
(c) SiO₄⁴⁻ ,PO₄³⁻ ,ClO₄⁻ ,SO₄²⁻ - - - -
(d) SiO₄⁴⁻ ,SO₄²⁻ ,PO₄³⁻ ,ClO₄⁻

Answers

Answered by brokendreams
0

The correct order of bond length is

Explanation:

  • The length of a covalent bond depends on the bond order of the elements.
  • The bond order is defined as the half of difference of electrons in bonding orbital and antibonding orbital.
  • Here, four species are given which are SiO₄4⁻, PO₄³⁻, SO₄²⁻and ClO₄⁻.
  • In SiO₄4⁻, the bond order of silicon and oxygen is 1.
  • In PO₄³⁻, the bond order is 1.25.
  • In SO₄²⁻, the bond order is 1.5.
  • In ClO₄⁻, the bond order is 3.5.
  • So,the trend of bond length is SiO₄⁴⁻ ,PO₄³⁻ ,SO₄²⁻ ,ClO₄⁻.

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Answered by dhanyasumesh140
0

Answer:

the answer is option-B , hope it helps you

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