Question

Arrange the following rational numbers in ascending order 3/5 ,4/7,-4/9,-8/3.​

Answer 1

Answer:

hope it's help you....

Answer 2

$Given \:rational \:numbers \: \frac{3}{5} , \frac{4}{7} ,\frac{-4}{9} ,\frac{-8}{3}$

$i) Take \: \frac{-4}{9} ,\frac{-8}{3}$

$LCM \:of \: 9, 3 \: is \: 9$

$\frac{-4}{9} \: --(1)$

$\frac{-8}{3} = \frac{ -8 \times 3}{3 \times 3 } = \frac{-24}{9} \: --(2)$

/* From (1) and (2)*/

$\frac{-24}{9} \lt \frac{-4}{9}$

$\blue { \frac{-8}{3} \lt \frac{-4}{9} }$

$ii) Take \: \frac{3}{5} ,\frac{4}{7}$

$LCM \: of \: 5 \: and \: 7 = 35$

$\frac{3}{5} = \frac{3\times 7}{5\times 7} = \frac{21}{35} \: --(3)$

$\frac{4}{7} = \frac{4\times 5}{7\times 5} = \frac{20}{35} \: --(4)$

/* From (3) and (4) */

$\frac{20}{35} \lt \frac{21}{35}$

$\blue { \frac{4}{7} \lt \frac{3}{5} }$

Therefore.,

$\underline{\pink{ Ascending \:order \:of \: rational \: numbers : }}$

$\green { \frac{-8}{3} \lt \frac{-4}{9} \lt \frac{4}{7} \lt \frac{3}{5} }$

•••♪