Question

Arrange the following species in the decreasing order of number of lone pairs present on central atom (a)I-3 (b) I+3(c) O3 (d) N20​

Answer 1

explanation:

H= 21

[V+M−C+A]

where,

H= Number of orbitals involved in hybridization.

V=Valence electrons of the central atom.

M- Number of monovalent atoms linked to a central atom.

C= Charge of a cation.

A= Charge of an anion.

Consider the hybridization and shape of the options:-

A) I 3−

H= 21

[7+2+1]=5.

⇒sp

3

d hybridized state with 3 lone pairs.

Linear in shape.

It has 2 bond pairs.

Answer 2

step by step is answer ok