Question

Arrange the following speeds in increasing order (keeping the least speed first)1 ) an athlete running with speed of 10m/s2)a bicycle moving with a speed of 200m/s3)a scooter moving with a speed of30km/h

Answer 1

The order of the speed is speed of scooter < speed of athlete < speed of bicycle.

Given data suggest that there are three situations which are to be arranged in increasing order with respect to their speed.  So we have first situation, where the athlete is running at a speed of 10 m/s. The second situation is that the bicycle is moving at a speed 200 m/s.  

The third situation is where a scooter moves at a speed of 30 km/hr. So in third situation, speed to be converted to m/s in order to compare.  

So, $speed3 =30\ \mathrm{km} / \mathrm{hr} \times \frac{1000 \mathrm{m}}{3600 \mathrm{sec}}=30 \times \frac{5}{18}=\frac{150}{18}=8.33\ \mathrm{m} / \mathrm{s}$. And, speed1 = 10 m/s and speed2 = 200 m/s so the order of speed is speed3 < speed1 < speed2.  

i.e. speed of scooter < speed of athlete < speed of bicycle.

Answer 2

Answer:

Answer is (ii), (iii), (i)

Explanation:

(i) Speed of athlete = 10 m/s

(ii) Speed of bicycle = 200 m/min = 200/60 =3.33m/s

(iii) Speed of scooter = 30× 5/18 = 25/3 = 8.33 m/s

So, increasing order is (ii), (iii), (i)