Arrange the following steps to construct the quadrilateral ABCD with BC=4.5cm, AB=3.5cm, CD=3cm,
i) With B as centre draw an arc of radius 3.5 cm intersecting BX at a point A. Similarly with C as centre, draw an arc of radius 3 cm intersecting CY at point D.
ii) Draw < CBX =90 deg at point B and
iii) Join DA.
iv) Draw a line segment of length 4.5cm and name it as BC.
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I think it won't be possible
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