Question

Arrange the following surds in ascending order :
3√4, 6√5  and 4√6
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Answer 1

SOLUTION:-

•The orders of the above surds are 3, 6 and 4. 

•The least common multiple of (3, 6 and 4) is 12.

•So, we have to make the order of each surd as 12. 

Then, 

³√4  =  ³×⁴√(44)  =  ¹²√256

⁶√5  =  ⁶ײ√(52)  =  ¹²√25

⁴√6  =  ⁴׳√(63)  =  ¹²√216

•Now, the given two surds are expressed in the same order. 

•Arrange the radicands in ascending order : 

25, 216, 256  

Then, 

¹²√25, ¹²√216, ¹²√256

•Therefore, the ascending order of the given surds is 

⁶√5, ⁴√6, ³√4