Question

arrange the orbitals 3s, 4d and 5p in term of (n+L) rules​

Answer 1

Answer:

3s >4d>5p

Explanation:

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Answer 2

The arrangement of the orbitals according to (n+l) rule is - 3s<4d<5p.

• As the value of (n+l) increases the energy of the orbital also increases and for same value of (n+l) as the value of n increases energy also increases.
• Here n is principal quantum number and l is azimuthal quantum number.
• For s,p and d orbital the value of l is 0,1,2.
• The (n+l) value for 3s is (3+0)=3.
• The (n+l) value for 4d is (4+2)=6.
• The (n+l) value for 5p is (5+1)=6.
• As 5p has highest value of (n+l) and n thus it have highest energy.
• 3s has lowest energy.
• The energy order is 3s<4d<5p.